5) Calculate the mass of silver phosphate produced from 36.2g of silver acetate if sodium phosphate and silver acetate produce silver phosphate and sodium acetate in the reaction Na_(3)PO_(4)+3AgC_(2)H_(3)O_(2)arrow Ag_(3)PO_(4)+3NaC_(2)H_(3)O_(2)

To calculate the mass of silver phosphate produced from 36.2g of silver acetate, we need to follow these steps:<br /><br />1. Determine the molar mass of silver acetate (AgC2H3O2) and silver phosphate (Ag3PO4).<br />2. Convert the mass of silver acetate to moles using its molar mass.<br />3. Use the stoichiometry of the balanced chemical equation to find the moles of silver phosphate produced.<br />4. Convert the moles of silver phosphate to grams using its molar mass.<br /><br />Let's go through these steps:<br /><br />1. Molar masses:<br /> - Silver acetate (AgC2H3O2): 166.97 g/mol (Ag) + 2(12.01 g/mol) + 3(1.01 g/mol) + 2(16.00 g/mol) = 166.97 g/mol<br /> - Silver phosphate (Ag3PO4): 3(166.97 g/mol) + 30.97 g/mol (P) + 4(16.00 g/mol) = 418.58 g/mol<br /><br />2. Convert the mass of silver acetate to moles:<br /> Moles of silver acetate = 36.2 g / 166.97 g/mol = 0.216 mol<br /><br />3. Use the stoichiometry of the balanced chemical equation:<br /> According to the balanced equation, 3 moles of silver acetate produce 1 mole of silver phosphate.<br /> Moles of silver phosphate = 0.216 mol AgC2H3O2 * (1 mol Ag3PO4 / 3 mol AgC2H3O2) = 0.072 mol Ag3PO4<br /><br />4. Convert the moles of silver phosphate to grams:<br /> Mass of silver phosphate = 0.072 mol * 418.58 g/mol = 30.0 g<br /><br />Therefore, the mass of silver phosphate produced from 36.2g of silver acetate is 30.0 grams.