Which best approximates the relationship between the speed of the car and stopping distance. As the speed of the car doubles, the distance it takes the car to stop also doubles quadruples decreases, becoming half as much Increases, more than doubles but doesn't quadruple Increases, but less than doubles

## Step 1<br />The problem is asking us to determine the relationship between the speed of a car and its stopping distance. This is a question about the principles of physics, specifically the concept of kinetic energy.<br /><br />## Step 2<br />The kinetic energy of an object is given by the formula:<br />### \( KE = \frac{1}{2}mv^2 \)<br />where \( m \) is the mass of the object and \( v \) is its velocity.<br /><br />## Step 3<br />When a car stops, its kinetic energy is converted into other forms of energy, such as heat and sound. The stopping distance of the car is directly related to the kinetic energy it possesses.<br /><br />## Step 4<br />If the speed of the car doubles, the kinetic energy of the car will increase by a factor of four (since the speed is squared in the formula). This means that the stopping distance of the car will also increase by a factor of four.