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3. (18 ris) Using the same equation above, calculate the number of grams of HCI formed when les of Zinc (Zn)are used. square
Solución

Leonardomaestro · Tutor durante 5 años

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To calculate the number of grams of HCl formed when 18 grams of Zinc (Zn) are used, we need to follow these steps:<br /><br />1. Write the balanced chemical equation for the reaction between Zinc (Zn) and Hydrochloric acid (HCl).<br />2. Calculate the molar mass of Zinc (Zn) and Hydrochloric acid (HCl).<br />3. Convert the given mass of Zinc (Zn) to moles using its molar mass.<br />4. Use the stoichiometry of the balanced chemical equation to determine the moles of HCl formed.<br />5. Convert the moles of HCl to grams using its molar mass.<br /><br />Let's go through these steps:<br /><br />1. The balanced chemical equation for the reaction between Zinc (Zn) and Hydrochloric acid (HCl) is:<br /> Zn + 2HCl → ZnCl2 + H2<br /><br />2. The molar mass of Zinc (Zn) is 65.38 g/mol, and the molar mass of Hydrochloric acid (HCl) is 36.46 g/mol.<br /><br />3. Convert the given mass of Zinc (Zn) to moles:<br /> Moles of Zn = 18 g / 65.38 g/mol = 0.276 mol<br /><br />4. According to the balanced chemical equation, 1 mole of Zinc (Zn) reacts with 2 moles of Hydrochloric acid (HCl). Therefore, the moles of HCl formed will be:<br /> Moles of HCl = 0.276 mol Zn × 2 mol HCl/mol Zn = 0.552 mol HCl<br /><br />5. Convert the moles of HCl to grams:<br /> Mass of HCl = 0.552 mol × 36.46 g/mol = 20.1 g<br /><br />Therefore, the number of grams of HCl formed when 18 grams of Zinc (Zn) are used is 20.1 grams.
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