Pagina de inicio
/
Química
/
3. (18 ris) Using the same equation above, calculate the number of grams of HCI formed when les of Zinc (Zn)are used. square

Problemas

3. (18 ris) Using the same equation above, calculate the number of grams of HCI formed when
les of Zinc (Zn)are used.
square

3. (18 ris) Using the same equation above, calculate the number of grams of HCI formed when les of Zinc (Zn)are used. square

Solución

avatar
Leonardomaestro · Tutor durante 5 años
expert verifiedVerificación de expertos
4.5 (249 votos)

Responder

To calculate the number of grams of HCl formed when 18 grams of Zinc (Zn) are used, we need to follow these steps:<br /><br />1. Write the balanced chemical equation for the reaction between Zinc (Zn) and Hydrochloric acid (HCl).<br />2. Calculate the molar mass of Zinc (Zn) and Hydrochloric acid (HCl).<br />3. Convert the given mass of Zinc (Zn) to moles using its molar mass.<br />4. Use the stoichiometry of the balanced chemical equation to determine the moles of HCl formed.<br />5. Convert the moles of HCl to grams using its molar mass.<br /><br />Let's go through these steps:<br /><br />1. The balanced chemical equation for the reaction between Zinc (Zn) and Hydrochloric acid (HCl) is:<br /> Zn + 2HCl → ZnCl2 + H2<br /><br />2. The molar mass of Zinc (Zn) is 65.38 g/mol, and the molar mass of Hydrochloric acid (HCl) is 36.46 g/mol.<br /><br />3. Convert the given mass of Zinc (Zn) to moles:<br /> Moles of Zn = 18 g / 65.38 g/mol = 0.276 mol<br /><br />4. According to the balanced chemical equation, 1 mole of Zinc (Zn) reacts with 2 moles of Hydrochloric acid (HCl). Therefore, the moles of HCl formed will be:<br /> Moles of HCl = 0.276 mol Zn × 2 mol HCl/mol Zn = 0.552 mol HCl<br /><br />5. Convert the moles of HCl to grams:<br /> Mass of HCl = 0.552 mol × 36.46 g/mol = 20.1 g<br /><br />Therefore, the number of grams of HCl formed when 18 grams of Zinc (Zn) are used is 20.1 grams.
Haz clic para calificar: