Question S (a) points) Asolution of H_(3)C_(6)H_(5)O_(7) at 1.8 M is diluted from its original volume of 40.7 mL by adding 1165 mL M1=1.8 M V1=40.7mL V2=116.5mL What is the resulting concentration of this solution (M2) __ M (Answer with 2 significant figures) Blank 1: 1.8 Blank 2 40.7 Blank 3: 116.5 Blank 4

To find the resulting concentration of the solution after dilution, we can use the formula:<br /><br />\[ M_1 \times V_1 = M_2 \times V_2 \]<br /><br />Where:<br />- \( M_1 \) is the initial concentration (1.8 M)<br />- \( V_1 \) is the initial volume (40.7 mL)<br />- \( M_2 \) is the final concentration<br />- \( V_2 \) is the final volume (116.5 mL)<br /><br />Rearranging the formula to solve for \( M_2 \):<br /><br />\[ M_2 = \frac{M_1 \times V_1}{V_2} \]<br /><br />Substituting the given values:<br /><br />\[ M_2 = \frac{1.8 \, \text{M} \times 40.7 \, \text{mL}}{116.5 \, \text{mL}} \]<br /><br />\[ M_2 = \frac{73.26}{116.5} \]<br /><br />\[ M_2 \approx 0.63 \, \text{M} \]<br /><br />So, the resulting concentration of the solution is approximately 0.63 M.