Balicylic acid (C_(7)H_(6)O_(3)) reacts with acefic andyydride (C_(4)H_(8)O_(3)) to form accitylialicylic acid (C_(9)H_(8)O_(4)) 2C_(7)H_(6)O_(3)(aq)+C_(9)H_(6)O_(3)(aq)arrow 2C_(9)H_(8)O_(4)(aq)+H_(2)O(l) What is the liming reactant if 700g of C_(7)H_(6)O_(3) and 80.0g of C_(4)H_(6)O_(3) read? water salicylic acid acetic anhydride acetylsalicylic acid

To determine the limiting reactant, we need to compare the amount of each reactant available to the amount required by the balanced chemical equation.<br /><br />First, let's calculate the molar mass of each compound:<br />- Salicylic acid $(C_{7}H_{6}O_{3})$: $7 \times 12.01 + 6 \times 1.01 + 3 \times 16.00 = 138.12 \, \text{g/mol}$<br />- Acetic anhydride $(C_{4}H_{6}O_{3})$: $4 \times 12.01 + 6 \times 1.01 + 3 \times 16.00 = 102.09 \, \text{g/mol}$<br /><br />Next, let's calculate the number of moles of each reactant:<br />- Moles of salicylic acid: $\frac{700 \, \text{g}}{138.12 \, \text{g/mol}} = 5.06 \, \text{mol}$<br />- Moles of acetic anhydride: $\frac{80.0 \, \text{g}}{102.09 \, \text{g/mol}} = 0.78 \, \text{mol}$<br /><br />Now, let's compare the mole ratio from the balanced chemical equation:<br />- According to the balanced equation, 2 moles of salicylic acid react with 1 mole of acetic anhydride.<br /><br />To find the limiting reactant, we need to determine which reactant is present in the smaller amount compared to the required amount based on the mole ratio.<br /><br />In this case, the mole ratio of salicylic acid to acetic anhydride is 2:1. Since we have 5.06 moles of salicylic acid and only 0.78 moles of acetic anhydride, acetic anhydride is the limiting reactant.<br /><br />Therefore, the limiting reactant is acetic anhydride.