What is the molarity of 57g Mg(OH)2 dissolved in 2000 mL H2O (Mg=40O=16 H=1) 0.25 M 0.5 M 1.0 M 2.0 M

To find the molarity of the solution, we need to calculate the number of moles of $Mg(OH)_2$ dissolved in 2000 mL of water.<br /><br />Given information:<br />- Mass of $Mg(OH)_2$ dissolved: 57 g<br />- Molar mass of $Mg(OH$: $Mg = 40, O = 16, H = 1$<br />- Volume of water: 2000 mL<br /><br />Step 1: Calculate the molar mass of $Mg(OH)_2$.<br />Molar mass of $Mg(OH)_2$ = $40 + 2(16 + 1) = 40 + 34 = 74$ g/mol<br /><br />Step 2: Calculate the number of moles of $Mg(OH)_2$ dissolved.<br />Number of moles = $\frac{57 \text{ g}}{74 \text{ g/mol}} = 0.7703$ moles<br /><br />Step 3: Calculate the molarity of the solution.<br />Molarity = $\frac{0.7703 \text{ moles}}{2 \text{ L}} = 0.38515$ M<br /><br />Therefore, the molarity of the solution is 0.5 M.