How many grams are there in 7.5times 10^23 molecules of H_(2)SO_(4) 6) How many molecules are there in 122 grams of Cu(NO_(3))_(2) 7) How many grams are there in 9.4times 10^25 molecules of H_(2) 8) How many molecules are there in 230 grams of CoCl_(2) WKSOO1X012 C 2000 Cavalcade Publishing (http://www ,cavalcadepublishing.com)

To solve these problems, we need to use the concept of molar mass and Avogadro's number.<br /><br />1. How many grams are there in $7.5\times 10^{23}$ molecules of $H_{2}SO_{4}$?<br /><br />First, we need to find the molar mass of $H_{2}SO_{4}$. The molar mass of $H_{2}SO_{4}$ is 98.08 g/mol.<br /><br />Next, we need to find the number of moles of $H_{2}SO_{4}$ in $7.5\times 10^{23}$ molecules. We can use Avogadro's number, which is $6.022\times 10^{23}$ molecules/mol.<br /><br />Number of moles = $\frac{7.5\times 10^{23}}{6.022\times 10^{23}}$ = 1.25 moles<br /><br />Finally, we can calculate the mass of $H_{2}SO_{4}$ by multiplying the number of moles by the molar mass.<br /><br />Mass = 1.25 moles * 98.08 g/mol = 122.6 grams<br /><br />Therefore, there are 122.6 grams in $7.5\times 10^{23}$ molecules of $H_{2}SO_{4}$.<br /><br />2. How many molecules are there in 122 grams of $Cu(NO_{3})_{2}$?<br /><br />First, we need to find the molar mass of $Cu(NO_{3})_{2}$. The molar mass of $Cu(NO_{3})_{2}$ is 187.56 g/mol.<br /><br />Next, we need to find the number of moles of $Cu(NO_{3})_{2}$ in 122 grams. We can use the formula:<br /><br />Number of moles = $\frac{Mass}{Molar mass}$<br /><br />Number of moles = $\frac{122}{187.56}$ = 0.65 moles<br /><br />Finally, we can calculate the number of molecules by multiplying the number of moles by Avogadro's number.<br /><br />Number of molecules = 0.65 moles * $6.022\times 10^{23}$ molecules/mol = $3.93\times 10^{23}$ molecules<br /><br />Therefore, there are $3.93\times 10^{23}$ molecules in 122 grams of $Cu(NO_{3})_{2}$.<br /><br />3. How many grams are there in $9.4\times 10^{25}$ molecules of $H_{2}$?<br /><br />First, we need to find the molar mass of $H_{2}$. The molar mass of $H_{2}$ is 2.02 g/mol.<br /><br />Next, we need to find the number of moles of $H_{2}$ in $9.4\times 10^{25}$ molecules. We can use Avogadro's number, which is $6.022\times 10^{23}$ molecules/mol.<br /><br />Number of moles = $\frac{9.4\times 10^{25}}{6.022\times 10^{23}}$ = 156.1 moles<br /><br />Finally, we can calculate the mass of $H_{2}$ by multiplying the number of moles by the molar mass.<br /><br />Mass = 156.1 moles * 2.02 g/mol = 314.8 grams<br /><br />Therefore, there are 314.8 grams in $9.4\times 10^{25}$ molecules of $H_{2}$.<br /><br />4. How many molecules are there in 230 grams of $CoCl_{2}$?<br /><br />First, we need to find the molar mass of $CoCl_{2}$. The molar mass of $CoCl_{2}$ is 129.9 g/mol.<br /><br />Next, we need to find the number of moles of $CoCl_{2}$ in 230 grams. We can use the formula:<br /><br />Number of moles = $\frac{Mass}{Molar mass}$<br /><br />Number of moles = $\frac{230}{129.9}$ = 1.77 moles<br /><br />Finally, we can calculate the number of molecules by multiplying the number of moles by Avogadro's number.<br /><br />Number of molecules = 1.77 moles * $6.022\times 10^{23}$ molecules/mol = $1.07\times 10^{24}$ molecules<br /><br />Therefore, there are $1.07\times 10^{24}$ molecules in 230 grams of $CoCl_{2}$.