Quention 3 points) Asolution of H_(3)C_(6)H_(5)O_(7) at 1.8 M is diluted from its original volume of 407 mL by adding 116.5 mL M1=underline ( )M V1=underline ( )mL V_(2)=underline ( )mL What is the resulting concentration of this solution (M2) __ M (Answer with 2 significant figures) Blank 1 Blank 2 Blank 3 Blank 4

To solve this problem, we can use the dilution formula:<br /><br />$M_1V_1 = M_2V_2$<br /><br />where:<br />$M_1$ = initial concentration (1.8 M)<br />$V_1$ = initial volume (407 mL)<br />$M_2$ = final concentration (unknown)<br />$V_2$ = final volume (407 mL + 116.5 mL = 523.5 mL)<br /><br />Substituting the given values into the formula, we get:<br /><br />$1.8 \, \text{M} \times 407 \, \text{mL} = M_2 \times 523.5 \, \text{mL}$<br /><br />Solving for $M_2$, we get:<br /><br />$M_2 = \frac{1.8 \, \text{M} \times 407 \, \text{mL}}{523.5 \, \text{mL}}$<br /><br />$M_2 = 1.38 \, \text{M}$<br /><br />Therefore, the resulting concentration of the solution is 1.38 M.