D. 2. What is the molar mass of Ca_(3)(PO_(4))_(2) Din) 3108 Din) 3428 Do 2798 2468

The molar mass of $Ca_{3}(PO_{4})_{2}$ is 3108 g/mol.<br /><br />Explanation:<br />The molar mass of a compound is the sum of the molar masses of its constituent atoms. In this case, the compound is $Ca_{3}(PO_{4})_{2}$, which consists of 3 calcium atoms (Ca), 2 phosphate groups (PO4).<br /><br />The molar mass of calcium (Ca) is approximately 40.08 g/mol, and the molar mass of oxygen (O) is approximately 16.00 g/mol. The molar mass of phosphorus (P) is approximately 30.97 g/mol.<br /><br />To calculate the molar mass of $Ca_{3}(PO_{4})_{2}$, we need to multiply the molar mass of each atom by the number of times it appears in the compound and then add them together.<br /><br />Molar mass of $Ca_{3}(PO_{4})_{2}$ = (3 × 40.08 g/mol) + (2 × (30.97 g/mol + 4 × 16.00 g/mol))<br />= 120.24 g/mol + 2 × (30.97 g/mol + 64.00 g/mol)<br />= 120.24 g/mol + 2 × 94.97 g/mol<br />= 120.24 g/mol + 189.94 g/mol<br />= 310.18 g/mol<br /><br />Therefore, the molar mass of $Ca_{3}(PO_{4})_{2}$ is 3108 g/mol.