How many moles are in 60.5 g of Ca(OH)_(2) 816 mol 1.08 mol 4200 mol 35 mol

To determine the number of moles in 60.5 g of \(Ca(OH)_2\), we need to use the molar mass of \(Ca(OH)_2\).<br /><br />First, let's calculate the molar mass of \(Ca(OH)_2\):<br />- Calcium (Ca): 40.08 g/mol<br />- Oxygen (O): 16.00 g/mol<br />- Hydrogen (H): 1.01 g/mol<br /><br />The molar mass of \(Ca(OH)_2\) is:<br />\[ 40.08 + (2 \times 16.00) + (2 \times 1.01) = 40.08 + 32.00 + 2.02 = 74.10 \, \text{g/mol} \]<br /><br />Next, we use the formula to find the number of moles:<br />\[ \text{Number of moles} = \frac{\text{Mass}}{\text{Molar mass}} \]<br /><br />Substitute the given values:<br />\[ \text{Number of moles} = \frac{60.5 \, \text{g}}{74.10 \, \text{g/mol}} \approx 0.815 \, \text{mol} \]<br /><br />Therefore, the number of moles in 60.5 g of \(Ca(OH)_2\) is approximately 0.815 mol.<br /><br />So, the correct answer is:<br />\[ \boxed{0.815 \, \text{mol}} \]