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If a ball has a temp of 288 (in Kelvin)be if the pressure is changed from 1.06 atm to 9.20 atmand solum remains constant.
2094.22"
Formula 1 point If a ball has a temp of 288 (in Kelvin)be if the pressure is changed from 1.06 atm to 9.20 atmand solum remains constant. 2094.22
Solución
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Jerónimoprofessionell · Tutor durante 6 años
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To solve this problem, we can use the ideal gas law, which states that the pressure of a gas is directly proportional to its temperature, provided the volume and the amount of gas remain constant. The formula for this relationship is:<br /><br />P1/T1 = P2/T2<br /><br />Where:<br />P1 is the initial pressure<br />T1 is the initial temperature<br />P2 is the final pressure<br />T2 is the final temperature<br /><br />Given information:<br />- Initial temperature (T1) = 288 K<br />- Initial pressure (P1) = 1.06 atm<br />- Final pressure (P2) = 9.20 atm<br /><br />We need to find the final temperature (T2).<br /><br />Substituting the given values into the formula:<br /><br />P1/T1 = P2/T2<br />1.06 atm / 288 K = 9.20 atm / T2<br />T2 = (9.20 atm × 288 K) / 1.06 atm<br />T2 = 2,694.34 K<br /><br />Therefore, the final temperature of the ball when the pressure is changed from 1.06 atm to 9.20 atm is 2,694.34 K.
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