Given a gas is at 5 atm and 7 L, what is the pressure of the gas when volume changes to 25 L? 1.4 atm 25 atm 7.0 atm 4.1 atm

This question is about Boyle's Law, which states that the pressure and volume of a gas have an inverse relationship when temperature is held constant. If the volume of the gas increases, the pressure decreases and vice versa. The formula for Boyle's Law is P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume. In this case, the initial pressure (P1) is 5 atm, the initial volume (V1) is 7 L, and the final volume (V2) is 25 L. We need to find the final pressure (P2). Plugging the given values into the formula, we get 5 atm * 7 L = P2 * 25 L. Solving for P2, we get P2 = (5 atm * 7 L) / 25 L = 1.4 atm. Therefore, the pressure of the gas when the volume changes to 25 L is 1.4 atm.