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5 Formula 1 point If a ball has a temp of 304 K what will its temperature (in Kelvin)be if the pressure is changed from 1.65 atm to 8.95 atm and volume remains constant. Type your answer..

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5
Formula 1 point
If a ball has a temp of 304 K what will its temperature (in Kelvin)be if the pressure is changed from 1.65 atm to 8.95 atm and volume remains constant.
Type your answer..

5 Formula 1 point If a ball has a temp of 304 K what will its temperature (in Kelvin)be if the pressure is changed from 1.65 atm to 8.95 atm and volume remains constant. Type your answer..

Solución

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Alfonsoélite · Tutor durante 8 años
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The final temperature of the ball, when the pressure is changed from 1.65 atm to 8.95 atm and the volume remains constant, is approximately 1668.18 K.

Explicar

## Step 1<br />The problem involves the application of Gay-Lussac's Law, which states that the pressure of a gas is directly proportional to its absolute temperature, provided the volume remains constant. This can be mathematically represented as:<br />### \( \frac{P1}{T1} = \frac{P2}{T2} \)<br />where \( P1 \) and \( T1 \) are the initial pressure and temperature, and \( P2 \) and \( T2 \) are the final pressure and temperature.<br /><br />## Step 2<br />In this problem, we are given the initial temperature \( T1 = 304K \), the initial pressure \( P1 = 1.65atm \), and the final pressure \( P2 = 8.95atm \). We are asked to find the final temperature \( T2 \).<br /><br />## Step 3<br />We can rearrange the Gay-Lussac's Law equation to solve for \( T2 \):<br />### \( T2 = \frac{P2 \times T1}{P1} \)<br /><br />## Step 4<br />Substitute the given values into the equation:<br />### \( T2 = \frac{8.95atm \times 304K}{1.65atm} \)<br /><br />## Step 5<br />Calculate the value of \( T2 \).
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