Multiple Choice 10 points If you start with 45 grams of ethylene (C_(2)H_(4)) how many grams of carbon dioxide (CO_(2)) will be produced? C_(2)H_(4)+3O_(2)2CO_(2)+2H_(2)O 35.368 23.57 g 212.14g 141.43g

This question is about stoichiometry, which is a section of chemistry that involves calculating the quantities of reactants and products in a chemical reaction. The balanced chemical equation given is:<br /><br />\[C_{2}H_{4} + 3O_{2} \rightarrow 2CO_{2} + 2H_{2}O\]<br /><br />From this equation, we can see that 1 mole of ethylene (C2H4) produces 2 moles of carbon dioxide (CO2). <br /><br />The molar mass of C2H4 is approximately 28.05 g/mol, and the molar mass of CO2 is approximately 44.01 g/mol. <br /><br />So, if we start with 45 grams of C2H4, we first need to convert this to moles by dividing by the molar mass of C2H4:<br /><br />\[45 g / 28.05 g/mol = 1.61 moles\]<br /><br />Since 1 mole of C2H4 produces 2 moles of CO2, 1.61 moles of C2H4 will produce 2 * 1.61 = 3.22 moles of CO2.<br /><br />Finally, we convert this back to grams by multiplying by the molar mass of CO2:<br /><br />\[3.22 moles * 44.01 g/mol = 141.43 g\]<br /><br />So, 45 grams of C2H4 will produce 141.43 grams of CO2.