Problemas

7.The frequency of Olive's periodic motion (in #7)is __ a. 0.20 Hz b. 0.40 Hz C. 2.5 Hz d. 5.0 Hz A 8. Wave period of 5.0 seconds corresponds to a frequency of __ Hz.A. 0.2 to b. 0.50 C. 0.02 o d. 0.050 e. 0.0020
Solución
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7. A<br />8. A
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## Step 1<br />The frequency of a periodic motion is defined as the number of cycles or oscillations that occur per unit time. It is usually measured in Hertz (Hz), where 1 Hz is equivalent to 1 cycle per second.<br /><br />## Step 2<br />For question 7, the frequency of Olive's periodic motion is given as 0.20 Hz. This means that Olive's motion completes 0.20 cycles per second.<br /><br />## Step 3<br />The wave period is the time it takes for one complete cycle of a wave to pass a given point. It is usually measured in seconds. The frequency and the wave period are inversely proportional to each other. This means that as the frequency increases, the wave period decreases, and vice versa.<br /><br />## Step 4<br />For question 8, the wave period is given as 5.0 seconds. To find the corresponding frequency, we need to take the reciprocal of the wave period. This is because the frequency is the number of cycles per second, and the wave period is the time for one cycle.<br /><br />### **The formula to calculate frequency is:**<br />### \( Frequency = \frac{1}{Period} \)<br /><br />## Step 5<br />Substituting the given wave period into the formula, we get:<br /><br />### \( Frequency = \frac{1}{5.0} = 0.2 \) Hz
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