FeS+HNO_(3)arrow Fe(NO_(3))_(2)+H_(2)S CheckEquation

To check the equation, we need to balance it by ensuring that the number of atoms of each element is the same on both sides of the equation.<br /><br />Given equation: $FeS+HNO_{3}\rightarrow Fe(NO_{3})_{2}+H_{2}S$<br /><br />Step 1: Balance the iron (Fe) atoms.<br />There is 1 Fe atom on the left side and 1 Fe atom on the right side. The Fe atoms are already balanced.<br /><br />Step 2: Balance the sulfur (S) atoms.<br />There is 1 S atom on the left side and 1 S atom on the right side. The S atoms are already balanced.<br /><br />Step 3: Balance the hydrogen (H) atoms.<br />There are 3 H atoms on the left side and 2 H atoms on the right side. To balance the H atoms, we need to multiply the $HNO_{3}$ by 2.<br /><br />$FeS+2HNO_{3}\rightarrow Fe(NO_{3})_{2}+H_{2}S$<br /><br />Step 4: Balance the nitrogen (N) atoms.<br />There are 2 N atoms on the left side and 2 N atoms on the right side. The N atoms are already balanced.<br /><br />The balanced equation is:<br />$FeS+2HNO_{3}\rightarrow Fe(NO_{3})_{2}+H_{2}S$<br /><br />Therefore, the equation is balanced.