What is the mass, in grams, of 0.450 moles of Sb? 35.5g 20.2 g 54.89 2.71times 10^wedge 23g 0.450 g

To find the mass of 0.450 moles of Sb (antimony), we need to use the m of mass of Sb is 121.76 g/mol.<br /><br />To, we can use the formula:<br /><br />Mass = Moles × Molar Mass<br /><br />Substituting the given values:<br /><br />Mass0les × 121.76 g/mol<br />Mass = 54.89 g<br /><br />Therefore, the mass of 0.450 moles of Sb is 54.89 grams.