__ 7. What is the molar mass of Mg_(3)(PO_(4))_(2) C. 357.8g/mol d. 262.855g/mol a. 143.58g/mol b 221.8g/mol

To calculate the molar mass of \( Mg_3(PO_4)_2 \), we sum up the atomic masses of all the atoms in the compound:<br /><br />1. Magnesium (\(Mg\)): \(24.305 \, g/mol\) × 3 = \(72.915 \, g/mol\)<br />2. Phosphorus (\(P\)): \(30.974 \, g/mol\) × 2 = \(61.948 \, g/mol\)<br />3. Oxygen (\(O\)): \(15.999 \, g/mol\) × 8 = \(127.992 \, g/mol\)<br /><br />Adding these together:<br />\( 72.915 + 61.948 + 127.992 = 262.855 \, g/mol \)<br /><br />**Correct answer: d. \(262.855 \, g/mol\)**