How long does it take a 2000-Kg car to stop from a velocity of 35m/s if a braking force of 4000 Newtons is used? p=mv m_(1)v_(1f)+m_(2)v_(2i)=m_(f)v_(1f)+m_(2)v_(2f) 10 seconds b 17.5 seconds 70 seconds d B.75 seconds Question 23 (1 point) Sug

To solve this problem, we need to use the principles of physics, specifically the concepts of momentum and Newton's second law.<br /><br />Given information:<br />- Mass of the car (m) = 2000 kg<br />- Initial velocity (v) = 35 m/s<br />- Braking force (F) = 4000 N<br /><br />Step 1: Calculate the acceleration (a) using Newton's second law.<br />Newton's second law states that the force applied to an object is equal to the mass of the object multiplied by its acceleration.<br />F = m × a<br />a = F / m<br />a = 4000 N / 2000 kg<br />a = 2 m/s²<br /><br />Step 2: Calculate the time (t) it takes for the car to stop.<br />The car's initial momentum is given by p_initial = m × v.<br />The car's final momentum is 0 (since the car comes to a stop).<br />Using the conservation of momentum:<br />p_initial = p_final<br />m × v = 0<br />t = v / a<br />t = 35 m/s / 2 m/s²<br />t = 17.5 seconds<br /><br />Therefore, the correct answer is:<br />b) 17.5 seconds