Type Coefficienets to Balance Equation here ->> square Ca(NO_(3))_(2)+square Cr_(2)(SO_(4))_(3)arrow square CaSO_(4)+square Cr(NO_(3))_(3)

To balance the chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />The unbalanced equation is:<br />$Ca(NO_{3})_{2} + Cr_{2}(SO_{4})_{3} \rightarrow CaSO_{4} + Cr(NO_{3})_{3}$<br /><br />To balance the equation, we need to find the coefficients that make the number of atoms of each element equal on both sides.<br /><br />Let's start by balancing the calcium (Ca) atoms. There is 1 Ca atom on the left side and 1 Ca atom on the right side. So, the coefficient for Ca(NO_{3})_{2} should be 1.<br /><br />Next, let's balance the chromium (Cr) atoms. There are 2 Cr atoms on the left side and 1 Cr atom on the right side. So, the coefficient for Cr(NO_{3})_{3} should be 2.<br /><br />Now, let's balance the nitrate (NO_{3}) groups. There are 2 NO_{3} groups on the left side and 6 NO_{3} groups on the right side. So, the coefficient for Ca(NO_{3})_{2} should be 3.<br /><br />Finally, let's balance the sulfate (SO_{4}) groups. There are 3 SO_{4} groups on the left side and 3 SO_{4} groups on the right side. So, the coefficient for Cr_{2}(SO_{4})_{3} should be 3.<br /><br />The balanced equation is:<br />$3Ca(NO_{3})_{2} + 3Cr_{2}(SO_{4})_{3} \rightarrow 3CaSO_{4} + 2Cr(NO_{3})_{3}$<br /><br />Therefore, the coefficients to balance the equation are:<br />$3Ca(NO_{3})_{2} + 3Cr_{2}(SO_{4})_{3} \rightarrow 3CaSO_{4} + 2Cr(NO_{3})_{3}$