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Select all answers that apply when describing the correct steps needed to solve the following problem. How many grams are in 3.25 moles of calcium carbonate (CaCO_(3)) Use the molar mass to go from moles to grams Calculate the number of molecules in 1 liter Calculate the molar mass of CaCO_(3) Use Avogadro's number to go from grams to liters Use 22.4 as the conversion factor to go from grams to moles

Problemas

Select all answers that apply when describing the correct steps needed to solve the following problem.
How many grams are in 3.25 moles of calcium carbonate (CaCO_(3))
Use the molar mass to go from moles to grams
Calculate the number of molecules in 1 liter
Calculate the molar mass of CaCO_(3)
Use Avogadro's number to go from grams to liters
Use 22.4 as the conversion factor to go from grams to moles

Select all answers that apply when describing the correct steps needed to solve the following problem. How many grams are in 3.25 moles of calcium carbonate (CaCO_(3)) Use the molar mass to go from moles to grams Calculate the number of molecules in 1 liter Calculate the molar mass of CaCO_(3) Use Avogadro's number to go from grams to liters Use 22.4 as the conversion factor to go from grams to moles

Solución

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Karinamaestro · Tutor durante 5 años
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3.4 (111 votos)

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### Calculate the molar mass of \(CaCO_{3}\)<br />### Use the molar mass to go from moles to grams

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## Step 1: Calculate the molar mass of \(CaCO_{3}\)<br />### The molar mass of \(CaCO_{3}\) is calculated by summing the atomic masses of calcium (Ca), carbon (C), and oxygen (O). The atomic masses are approximately 40.08 g/mol for Ca, 12.01 g/mol for C, and 16.00 g/mol for O. Since there are three oxygen atoms in \(CaCO_{3}\), the total molar mass is:<br />\[ \text{Molar mass of } CaCO_{3} = 40.08 + 12.01 + (3 \times 16.00) = 100.09 \, \text{g/mol} \]<br /><br />## Step 2: Use the molar mass to go from moles to grams<br />### To find the number of grams in 3.25 moles of \(CaCO_{3}\), multiply the number of moles by the molar mass:<br />\[ \text{Mass} = \text{Number of moles} \times \text{Molar mass} \]<br />\[ \text{Mass} = 3.25 \, \text{moles} \times 100.09 \, \text{g/mol} = 325.29 \, \text{grams} \]
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