A 41.0 mL barium hydroxide solution of molarity 3.41M is diluted with water to form 279 mL of the solution. Calculate the molarity of the solution.

To calculate the molarity of the solution after dilution, we can use the formula:<br /><br />M1V1 = M2V2:<br />M1 = initial molarity<br />V1 = initial volume<br />M2 = final molarity<br />V2 = final volume<br /><br />Given information:<br />- Initial molarity (M1) = 3.41 M<br />- Initial volume (V1) = 41.0 mL<br />- Final volume (V2) = 279 mL<br /><br />Substituting the values in the formula:<br /><br />M1V1 = M2V2<br />(3.41 M)(41.0 mL) = M2(279 mL)<br />M2 = (3.41 M)(41.0 mL) / (279 mL)<br />M2 = 0.505 M<br /><br />Therefore, the molarity of the solution after dilution is 0.505 M.