How many moles of CO_(2) will be produced if 3 moles of C_(2)H_(4) is used up as indicated by the equation: C_(2)H_(4)+3O_(2)arrow 2CO_(2)+2H_(2)O 3 moles of CO_(2) 9 moles of CO_(2) 2 moles of CO_(2) 6 moles of CO_(2)

To determine the number of moles of $CO_{2}$ produced when 3 moles of $C_{2}H_{4}$ are used up, we need to use the stoichiometric coefficients from the balanced chemical equation.<br /><br />The balanced chemical equation is:<br />$C_{2}H_{4}+3O_{2}\rightarrow 2CO_{2}+2H_{2}O$<br /><br />From the equation, we can see that for every 1 mole of $C_{2}H_{4}$, 2 moles of $CO_{2}$ are produced.<br /><br />Therefore, if 3 moles of $C_{2}H_{4}$ are used up, the number of moles of $CO_{2}$ produced will be:<br />$3 \text{ moles of } C_{2}H_{4} \times \frac{2 \text{ moles of } CO_{2}}{1 \text{ mole of } C_{2}H_{4}} = 6 \text{ moles of } CO_{2}$<br /><br />So, the correct answer is 6 moles of $CO_{2}$.