2. h(x)=x^2-4x-5 X-intercept(s): __ Y-intercept: __ Axis of Symmetry: __ Vertex: __ Max or Min Domain: __ Range: __

## Step 1:<br />The x-intercepts of a function are the values of x for which the function equals zero. In this case, we need to solve the equation \(x^{2}-4x-5=0\).<br /><br />## Step 2:<br />The y-intercept of a function is the value of the function when x equals zero. In this case, we need to evaluate \(h(0)\).<br /><br />## Step 3:<br />The axis of symmetry of a parabola is the vertical line that passes through the vertex of the parabola. For a quadratic function in the form \(f(x)=ax^{2}+bx+c\), the axis of symmetry is given by the formula \(x=-b/2a\).<br /><br />## Step 4:<br />The vertex of a parabola is the point where the parabola reaches its maximum or minimum value. For a quadratic function in the form \(f(x)=ax^{2}+bx+c\), the vertex is given by the point \((-b/2a, f(-b/2a))\).<br /><br />## Step 5:<br />The domain of a function is the set of all possible x-values. For a quadratic function, the domain is all real numbers.<br /><br />## Step 6:<br />The range of a function is the set of all possible y-values. For a quadratic function that opens upwards, the range is all y-values greater than or equal to the y-coordinate of the vertex.