11. Calculate the molarity of a solution prepared by dissolving 6.80 grams of AgNO3 in enough water to make 2.50 liters of solution. 1.6 M 0.16 M 0.016 M 16 M

## Step 1<br />To calculate the molarity of a solution, we need to know the number of moles of solute and the volume of the solution in liters. The formula for molarity (M) is given by:<br />### \(M = \frac{{\text{{moles of solute}}}}{{\text{{volume of solution in liters}}}}\)<br /><br />## Step 2<br />First, we need to calculate the number of moles of AgNO3. The molar mass of AgNO3 is 169.87 g/mol. Therefore, the number of moles of AgNO3 is given by:<br />### \(\text{{moles of AgNO3}} = \frac{{\text{{mass of AgNO3}}}}{{\text{{molar mass of AgNO3}}}} = \frac{{6.80 \text{{ g}}}}{{169.87 \text{{ g/mol}}}} = 0.04 \text{{ mol}}\)<br /><br />## Step 3<br />Next, we substitute the number of moles of AgNO3 and the volume of the solution into the molarity formula:<br />### \(M = \frac{{0.04 \text{{ mol}}}}{{2.50 \text{{ L}}}} = 0.016 \text{{ M}}\)