Ca(OH)_(2)+2HFarrow CaF_(2)+2H_(2)O If you were given 23.68g of calcium hydroxide for the following reaction your theoretical yield would be 12.79g HF. But.when this experiment was conducted, an actual yield of only 10.41g HF was collected. What would the percent yield be? 64.32% 81.39% 39.43%

To calculate the percent yield, you can use the formula:<br /><br />\[ \text{Percent Yield} = \left( \frac{\text{Actual Yield}}{\text{Theoretical Yield}} \right) \times 100\% \]<br /><br />Given:<br />- Theoretical Yield = 12.79g<br />- Actual Yield = 10.41g<br /><br />Now, plug these values into the formula:<br /><br />\[ \text{Percent Yield} = \left( \frac{10.41g}{12.79g} \right) \times 100\% \]<br /><br />\[ \text{Percent Yield} = \left( 0.8139 \right) \times 100\% \]<br /><br />\[ \text{Percent Yield} = 81.39\% \]<br /><br />So, the correct answer is:<br /><br />\[ 81.39\% \]