Conversions 1. If 2 moles o fH_(2)O react completely w with Na, how many moles of NaOH are produced? A. 1 mole B. 2 moles C. 3 moles D. 4 moles 2. How many grams of O_(2) are in 3 moles o fO_(2) (Molar mass of O=16g/mol) A. 48 grams B. 96 grams C. 32 grams D. 64 grams 3. In the reaction 2H_(2)+O_(2)arrow 2H_(2)O if you have 4 moles of H_(2), how many moles of H_(2)O can be produced? A. 2 moles B. 4 moles C. 6 moles D. 8 moles 4. What is the mass of 2moles of CO_(2) (C=12g/mol,O=16g/mol) A. 44 grams B. 88 grams C. 66 grams D. 22 grams 5. How many moles of NH_(3) are in 34 grams of NH_(3) (N=14g/mol,H=1g/mol) A. 2 moles B. 1 mole C. 3 moles D. 4 moles 6. In the reaction CaCO_(3)arrow CaO+CO_(2) how many moles of CO_(2) are produced from 5 moles of CaCO_(3) 7 A. 2. Smoles B. 10 moles

1. B. 2 moles<br />Explanation: The balanced chemical equation for the reaction between water (H2O) and sodium (Na) is:<br />2H2O + 2Na → 2NaOH + H2<br />From the equation, we can see that 2 moles of water (H2O) react with 2 moles of sodium (Na) to produce 2 moles of sodium hydroxide (NaOH). Therefore, the correct answer is B. 2 moles.<br /><br />2. B. 96 grams<br />Explanation: The molar mass of oxygen (O2) is 32 g/mol. To find the mass of 3 moles of oxygen (O2), we multiply the molar mass by the number of moles:<br />Mass = Molar mass × Number of moles<br />Mass = 32 g/mol × 3 moles = 96 grams<br />Therefore, the correct answer is B. 96 grams.<br /><br />3. B. 4 moles<br />Explanation: The balanced chemical equation for the reaction between hydrogen (H2) and oxygen (O2) is:<br />2H2 + O2 → 2H2O<br />From the equation, we can see that 2 moles of hydrogen (H2) react with 1 mole of oxygen (O2) to produce 2 moles of water (H2O). Therefore, if we have 4 moles of hydrogen (H2), we can produce 4 moles of water (H2O). The correct answer is B. 4 moles.<br /><br />4. B. 88 grams<br />Explanation: The molar mass of carbon dioxide (CO2) is calculated by adding the molar masses of carbon (C) and oxygen (O):<br />Molar mass of CO2 = Molar mass of C + 2 × Molar mass of O<br />Molar mass of CO2 = 12 g/mol + 2 × 16 g/mol = 44 g/mol<br />To find the mass of 2 moles of carbon dioxide (CO2), we multiply the molar mass by the number of moles:<br />Mass = Molar mass × Number of moles<br />Mass = 44 g/mol × 2 moles = 88 grams<br />Therefore, the correct answer is B. 88 grams.<br /><br />5. B. 1 mole<br />Explanation: The molar mass of ammonia (NH3) is calculated by adding the molar masses of nitrogen (N) and hydrogen (H):<br />Molar mass of NH3 = Molar mass of N + 3 × Molar mass of H<br />Molar mass of NH3 = 14 g/mol + 3 × 1 g/mol = 17 g/mol<br />To find the number of moles of ammonia (NH3) in 34 grams, we divide the mass by the molar mass:<br />Number of moles = Mass / Molar mass<br />Number of moles = 34 grams / 17 g/mol = 2 moles<br />Therefore, the correct answer is B. 1 mole.<br /><br />6. A. 5 moles<br />Explanation: In the given reaction, calcium carbonate (CaCO3) decomposes to produce calcium oxide (CaO) and carbon dioxide (CO2). From the balanced chemical equation, we can see that 1 mole of calcium carbonate (CaCO3) produces 1 mole of carbon dioxide (CO2). Therefore, if we have 5 moles of calcium carbonate (CaCO3), we can produce 5 moles of carbon dioxide (CO2). The correct answer is A. 5 moles.