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A1300 g sample of citric acid (H_(3)C_(6)H_(5)O_(7)) reacts with an excess of baking soda as shown in the equation H_(3)C_(6)H_(5)O_(7)+3NaHCO_(3)arrow 3CO_(2)+3H_(2)O+Na_(3)C_(8)H_(5)O_(7) What is the theoretical yield of carbon dioxide? 0.9939 2989 3.65 8939

Problemas

A1300 g sample of citric acid (H_(3)C_(6)H_(5)O_(7)) reacts with an excess of baking soda as shown in the equation
H_(3)C_(6)H_(5)O_(7)+3NaHCO_(3)arrow 3CO_(2)+3H_(2)O+Na_(3)C_(8)H_(5)O_(7)
What is the theoretical yield of carbon dioxide?
0.9939
2989
3.65
8939

A1300 g sample of citric acid (H_(3)C_(6)H_(5)O_(7)) reacts with an excess of baking soda as shown in the equation H_(3)C_(6)H_(5)O_(7)+3NaHCO_(3)arrow 3CO_(2)+3H_(2)O+Na_(3)C_(8)H_(5)O_(7) What is the theoretical yield of carbon dioxide? 0.9939 2989 3.65 8939

Solución

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Elianaprofessionell · Tutor durante 6 años
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To find the theoretical yield of carbon dioxide, we need to follow these steps:<br /><br />1. Calculate the molar mass of citric acid (H3C6H5O7) and baking soda (NaHCO3).<br />2. Convert the mass of citric acid to moles using its molar mass.<br />3. Use the stoichiometry of the balanced chemical equation to determine the moles of carbon dioxide produced.<br />4. Convert the moles of carbon dioxide to grams using its molar mass.<br /><br />Let's go through these steps:<br /><br />1. Molar masses:<br /> - Citric acid (H3C6H5O7): 192.12 g/mol<br /> - Baking soda (NaHCO3): 84.01 g/mol<br /> - Carbon dioxide (CO2): 44.01 g/mol<br /><br />2. Convert the mass of citric acid to moles:<br /> Moles of citric acid = 1300 g / 192.12 g/mol = 6.75 mol<br /><br />3. Use the stoichiometry of the balanced equation:<br /> According to the balanced equation, 1 mole of citric acid produces 3 moles of carbon dioxide.<br /> Moles of carbon dioxide = 6.75 mol * 3 = 20.25 mol<br /><br />4. Convert the moles of carbon dioxide to grams:<br /> Theoretical yield of carbon dioxide = 20.25 mol * 44.01 g/mol = 893.9 g<br /><br />Therefore, the theoretical yield of carbon dioxide is 893.9 g.
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