BONUS +10 POINTS) Using the given moles from #3 for MnO_(2) and HCl, calculate how many be produced. 0.86 mol of MnO_(2) produces __ grams of Cl_(2) 4.82 mol of HCl produces __ grams of Cl_(2)

## Step 1: <br />First, we need to understand the chemical reaction involved. The reaction between manganese dioxide (MnO2) and hydrochloric acid (HCl) can be represented as follows:<br /><br />### \(MnO_{2} + 4HCl \rightarrow MnCl_{2} + Cl_{2} + 2H_{2}O\)<br /><br />From the balanced chemical equation, we can see that 1 mole of MnO2 reacts with 4 moles of HCl to produce 1 mole of Cl2.<br /><br />## Step 2:<br />Now, let's calculate the amount of Cl2 produced from 0.86 moles of MnO2.<br /><br />Since 1 mole of MnO2 produces 1 mole of Cl2, 0.86 moles of MnO2 will produce 0.86 moles of Cl2.<br /><br />## Step 3:<br />Next, we need to convert the moles of Cl2 to grams. The molar mass of Cl2 is approximately 70.9 g/mol.<br /><br />So, the mass of Cl2 produced from 0.86 moles of MnO2 is \(0.86 \times 70.9 = 61.174\) grams.<br /><br />## Step 4:<br />Now, let's calculate the amount of Cl2 produced from 4.82 moles of HCl.<br /><br />Since 4 moles of HCl produce 1 mole of Cl2, 4.82 moles of HCl will produce \(4.82/4 = 1.205\) moles of Cl2.<br /><br />## Step 5:<br />Finally, we convert the moles of Cl2 to grams using the molar mass of Cl2.<br /><br />So, the mass of Cl2 produced from 4.82 moles of HCl is \(1.205 \times 70.9 = 85.4745\) grams.