Write the log equation as an exponential equation. You do not need to solve for x. log(x^2-3x-8)=3

To convert the logarithmic equation $log(x^{2}-3x-8)=3$ into an exponential equation, we need to understand the relationship between logarithms and exponents. The equation $log_b(a) = c$ is equivalent to $b^c = a$. In this case, the base of the logarithm is 10 (since it's a common logarithm), the argument is $x^{2}-3x-8$, and the result is 3.<br /><br />So, the exponential form of the given logarithmic equation is:<br /><br />$10^3 = x^{2}-3x-8$<br /><br />This is the exponential equation equivalent to the given logarithmic equation.