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Consider the reaction: CH_(4)+2O_(2)arrow CO_(2)+2H_(2)O Exactly 14.5 moles of CO_(2) are produced from burning how many moles of CH_(4) in excess oxygen? 14.5 moles 65.2 moles 29.0 moles 34.5 moles

Problemas

Consider the reaction:
CH_(4)+2O_(2)arrow CO_(2)+2H_(2)O
Exactly 14.5 moles of CO_(2) are produced from burning
how many moles of CH_(4) in excess oxygen?
14.5 moles
65.2 moles
29.0 moles
34.5 moles

Consider the reaction: CH_(4)+2O_(2)arrow CO_(2)+2H_(2)O Exactly 14.5 moles of CO_(2) are produced from burning how many moles of CH_(4) in excess oxygen? 14.5 moles 65.2 moles 29.0 moles 34.5 moles

Solución

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Francoprofessionell · Tutor durante 6 años
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To solve this problem, we need to use the stoichiometry of the balanced chemical equation.<br /><br />Given information:<br />- The balanced chemical equation is: $CH_{4}+2O_{2}\rightarrow CO_{2}+2H_{2}O$<br />- 14.5 moles of $CO_{2}$ are produced.<br /><br />Step 1: Determine the mole ratio between $CH_{4}$ and $CO_{2}$.<br />From the balanced equation, we can see that 1 mole of $CH_{4}$ produces 1 mole of $CO_{2}$.<br /><br />Step 2: Calculate the moles of $CH_{4}$ required to produce 14.5 moles of $CO_{2}$.<br />Moles of $CH_{4}$ required = Moles of $CO_{2}$ produced<br />Moles of $CH_{4}$ required = 14.5 moles<br /><br />Therefore, the correct answer is:<br />14.5 moles
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