(f) DO THIS PROBLEM WITHOUT MATH: If there are 42.4 g of lithium chloride, about how many moles and particles are present in the sample? Explain how you know.

To determine the number of moles and particles in a 42.4 g sample of lithium chloride (LiCl), we need to use the molar mass of LiCl.<br /><br />The molar mass of LiCl is approximately 42.39 g/mol. This means that 1 mole of LiCl has a mass of 42.39 g.<br /><br />To find the number of moles in the 42.4 g sample, we can use the formula:<br /><br />Number of moles = Mass of the sample / Molar mass of LiCl<br /><br />Plugging in the values, we get:<br /><br />Number of moles = 42.4 g / 42.39 g/mol ≈ 1 mole<br /><br />So, the 42.4 g sample of lithium chloride contains approximately 1 mole of LiCl.<br /><br />To find the number of particles (atoms or molecules) in the sample, we can use Avogadro's number, which is 6.022 x 10^23 particles per mole.<br /><br />Number of particles = Number of moles x Avogadro's number<br /><br />Plugging in the values, we get:<br /><br />Number of particles = 1 mole x 6.022 x 10^23 particles/mole ≈ 6.022 x 10^23 particles<br /><br />Therefore, the 42.4 g sample of lithium chloride contains approximately 1 mole and 6.022 x 10^23 particles.