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a. 1.35 mol of carbon disulfide (CS_(2))"
1. How many molecules are contained in each compound? a. 1.35 mol of carbon disulfide (CS_(2))
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Jaimeveterano · Tutor durante 10 años
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To determine the number of molecules in 1.35 mol of carbon disulfide (CS₂), we need to use Avogadro's number, which is \(6.022 \times 10^{23}\) molecules per mole.<br /><br />The calculation is as follows:<br /><br />\[ \text{Number of molecules} = \text{moles} \times \text{Avogadro's number} \]<br /><br />\[ \text{Number of molecules} = 1.35 \, \text{mol} \times 6.022 \times 10^{23} \, \text{molecules/mol} \]<br /><br />\[ \text{Number of molecules} = 8.1297 \times 10^{23} \, \text{molecules} \]<br /><br />So, 1.35 mol of carbon disulfide (CS₂) contains approximately \(8.1297 \times 10^{23}\) molecules.
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