If you want to throw a ball up 60 meters into the air, how fast must you initially throw it? 34.29m/s 58.29m/s 78.29m/s 98.29m/s

To solve this problem, we can use the kinematic equation for an object in free fall:<br /><br />v^2 = u^2 + 2as<br /><br />Where:<br />v = final velocity (0 m/s, since the ball reaches the maximum height)<br />u = initial velocity (unknown)<br />a = acceleration due to gravity (-9.8 m/s^2, negative since it acts downward)<br />s = displacement (60 m, upward)<br /><br />Plugging in the values, we get:<br /><br />0 = u^2 + 2(-9.8)(60)<br />0 = u^2 - 1176<br />u^2 = 1176<br />u = √1176<br />u ≈ 34.29 m/s<br /><br />Therefore, the correct answer is $34.29m/s$.