(11) SEP Use Models Use the law of conservation of mass to write and balance the chemical equation for the reaction of fluorine (F_(2)) with aqueous lithium bromide (LiBr) to produce liquid bromine (Br_(2)) and aqueous lithium fluoride (LiF)

To write and balance the chemical equation for the reaction of fluorine (F2) with aqueous lithium bromide (LiBr) to produce liquid bromine (Br2) and aqueous lithium fluoride (LiF), we need to follow the law of conservation of mass. This law states that the total mass of the reactants must be equal to the total mass of the products.<br /><br />The unbalanced chemical equation for this reaction is:<br /><br />F2 + LiBr → Br2 + LiF<br /><br />To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. <br /><br />First, let's balance the bromine atoms. There are 2 bromine atoms on the left side (in LiBr) and 2 bromine atoms on the right side (in Br2). So, the bromine atoms are already balanced.<br /><br />Next, let's balance the lithium atoms. There is 1 lithium atom on the left side (in LiBr) and 1 lithium atom on the right side (in LiF). So, the lithium atoms are already balanced.<br /><br />Finally, let's balance the fluorine atoms. There are 2 fluorine atoms on the left side (in F2) and 1 fluorine atom on the right side (in LiF). To balance the fluorine atoms, we need to have 2 molecules of LiF on the right side.<br /><br />The balanced chemical equation is:<br /><br />F2 + 2LiBr → Br2 + 2LiF<br /><br />This equation shows that 1 molecule of fluorine (F2) reacts with 2 molecules of lithium bromide (LiBr) to produce 1 molecule of liquid bromine (Br2) and 2 molecules of aqueous lithium fluoride (LiF).