What is the number of ammonia molecules made when 6 grams of hydrogen gas reacts with excess nitrogen? 3H_(2)+N_(2)longleftrightarrow 2NH_(3) 6times 10^23 24times 10^23 18times 10^23 12times 10^23 Question 7 What is the number of nitrogen molecules that reacted with excess hydrogen to make 2times 10^10 molecules of ammonia? 3H_(2)+N_(2)longleftrightarrow 2NH_(3) 2times 10^10 3times 10^10 1times 10^10 5times 10^9 1 pts

To solve these problems, we need to use chemical equation and the given information to determine the number of molecules of ammonia or nitrogen involved.<br /><br />Question 1:<br />What is the number of ammonia molecules made when 6 grams of hydrogen gas reacts with excess nitrogen?<br />$3H_{2}+N_{2}\longleftrightarrow 2NH_{3}$<br /><br />Given information:<br />- 6 grams of hydrogen gas (H2) is used.<br />- Excess nitrogen (N2) is present.<br /><br />To find the number of ammonia (NH3) molecules produced, we need to follow these steps:<br /><br />1. Calculate the number of moles of hydrogen gas (H2) using the given mass and the molar mass of hydrogen gas.<br />2. Use the balanced chemical equation to determine the stoichiometric relationship between hydrogen gas and ammonia.<br />3. Calculate the number of ammonia molecules produced based on the stoichiometric relationship.<br /><br />Step 1: Calculate the number of moles of hydrogen gas (H2)<br />Molar mass of hydrogen gas (H2) = 2.016 g/mol<br />Number of moles of hydrogen gas (H2) = 6 g / 2.016 g/mol = 2.976 mol<br /><br />Step 2: Use the balanced chemical equation to determine the stoichiometric relationship<br />The balanced chemical equation is:<br />$3H_{2}+N_{2}\longleftrightarrow 2NH_{3}$<br />This means that 3 moles of hydrogen gas (H2) react with 1 mole of nitrogen (N2) to produce 2 moles of ammonia (NH3).<br /><br />Step 3: Calculate the number of ammonia molecules produced<br />Number of moles of ammonia (NH3) = (2/3) × Number of moles of hydrogen gas (H2)<br />Number of moles of ammonia (NH3) = (2/3) × 2.976 mol = 1.992 mol<br />Number of ammonia molecules = 1.992 mol × 6.022 × 10^23 molecules/mol = 12.0 × 10^23 molecules<br /><br />Therefore, the number of ammonia molecules produced is 12 × 10^23.<br /><br />Question 2:<br />What is the number of nitrogen molecules that reacted with excess hydrogen to make $2\times 10^{10}$ molecules of ammonia?<br />$3H_{2}+N_{2}\longleftrightarrow 2NH_{3}$<br /><br />Given information:<br />- $2\times 10^{10}$ molecules of ammonia (NH3) are produced.<br />- Excess hydrogen (H2) is present.<br /><br />To find the number of nitrogen (N2) molecules that reacted, we need to follow these steps:<br /><br />1. Calculate the number of moles of ammonia (NH3) using the given number of molecules and Avogadro's number.<br />2. Use the balanced chemical equation to determine the stoichiometric relationship between ammonia and nitrogen.<br />3. Calculate the number of nitrogen molecules based on the stoichiometric relationship.<br /><br />Step 1: Calculate the number of moles of ammonia (NH3)<br />Number of moles of ammonia (NH3) = $2\times 10^{10}$ molecules / 6.022 × 10^23 molecules/mol = 3.32 × 10^-14 mol<br /><br />Step 2: Use the balanced chemical equation to determine the stoichiometric relationship<br />The balanced chemical equation is:<br />$3H_{2}+N_{2}\longleftrightarrow 2NH_{3}$<br />This means that 2 moles of ammonia (NH3) are produced from 1 mole of nitrogen (N2).<br /><br />Step 3: Calculate the number of nitrogen molecules<br />Number of moles of nitrogen (N2) = (1/2) × Number of moles of ammonia (NH3)<br />Number of moles of nitrogen (N2) = (1/2) × 3.32 × 10^-14 mol = 1.66 × 10^-14 mol<br />Number of nitrogen molecules = 1.66 × 10^-14 mol × 6.022 × 10^23 molecules/mol = 1 × 10^10 molecules<br /><br />Therefore, the number of nitrogen molecules that reacted with excess hydrogen to make $2\times 10^{10}$ molecules of ammonia is 1 × 10^10.