How many molecules are there in 2.3 grams of NH_(4)SO_(2)

To find the number of molecules in 2.3 grams of $NH_{4}SO_{2}$, we need to follow these steps:<br /><br />1. Calculate the molar mass of $NH_{4}SO_{2}$.<br />2. Convert the given mass of $NH_{4}SO_{2}$ to moles.<br />3. Use Avogadro's number to find the number of molecules.<br /><br />Step 1: Calculate the molar mass of $NH_{4}SO_{2}$.<br />The molar mass of $NH_{4}SO_{2}$ is calculated by adding the molar masses of each element in the compound:<br />$N = 14.01 \, \text{g/mol}$<br />$H = 1.01 \, \text{g/mol}$<br />$S = 32.07 \, \text{g/mol}$<br />$O = 16.00 \, \text{g/mol}$<br /><br />Molar mass of $NH_{4}SO_{2} = 14.01 + (4 \times 1.01) + 32.07 + (2 \times 16.00) = 66.09 \, \text{g/mol}$<br /><br />Step 2: Convert the given mass of $NH_{4}SO_{2}$ to moles.<br />Given mass of $NH_{4}SO_{2} = 2.3 \, \text{g}$<br />Moles of $NH_{4}SO_{2} = \frac{2.3 \, \text{g}}{66.09 \, \text{g/mol}} = 0.0348 \, \text{mol}$<br /><br />Step 3: Use Avogadro's number to find the number of molecules.<br />Avogadro's number = $6.022 \times 10^{23} \, \text{molecules/mol}$<br />Number of molecules = $0.0348 \, \text{mol} \times 6.022 \times 10^{23} \, \text{molecules/mol} = 2.09 \times 10^{22} \, \text{molecules}$<br /><br />Therefore, there are approximately $2.09 \times 10^{22}$ molecules in 2.3 grams of $NH_{4}SO_{2}$.