Find the product Simplify your answer. (3x+3)(3x-3) square

To find the product of \((3x+3)(3x-3)\), we can use the distributive property (also known as the FOIL method for binomials). Here's the step-by-step process:<br /><br />1. **First terms**: Multiply the first terms in each binomial.<br /> \[<br /> 3x \cdot 3x = 9x^2<br /> \]<br /><br />2. **Outer terms**: Multiply the outer terms in the binomials.<br /> \[<br /> 3x \cdot -3 = -9x<br /> \]<br /><br />3. **Inner terms**: Multiply the inner terms in the binomials.<br /> \[<br /> 3 \cdot 3x = 9x<br /> \]<br /><br />4. **Last terms**: Multiply the last terms in each binomial.<br /> \[<br /> 3 \cdot -3 = -9<br /> \]<br /><br />Now, combine all these products:<br />\[<br />9x^2 - 9x + 9x - 9<br />\]<br /><br />Notice that the middle terms \(-9x\) and \(+9x\) cancel each other out:<br />\[<br />9x^2 - 9<br />\]<br /><br />So, the simplified product is:<br />\[<br />\boxed{9x^2 - 9}<br />\]