Find the product. Simplify your answer. 7(-4y^2+3y+2) square

To find the product and simplify the expression \(7(-4y^{2}+3y+2)\), we need to distribute the 7 to each term inside the parentheses.<br /><br />First, distribute 7 to \(-4y^2\):<br />\[ 7 \cdot (-4y^2) = -28y^2 \]<br /><br />Next, distribute 7 to \(3y\):<br />\[ 7 \cdot 3y = 21y \]<br /><br />Finally, distribute 7 to 2:<br />\[ 7 \cdot 2 = 14 \]<br /><br />Now, combine all these results:<br />\[ 7(-4y^2 + 3y + 2) = -28y^2 + 21y + 14 \]<br /><br />So, the simplified answer is:<br />\[ \boxed{-28y^2 + 21y + 14} \]