Write the exponential equation as a logarithmic equation. 2^-3=(1)/(8) Answer Attemptiout of 3 square

## Step 1<br />The given equation is \(2^{-3}=\frac {1}{8}\). This is an exponential equation where the base is 2, the exponent is -3, and the result is \(\frac {1}{8}\).<br /><br />## Step 2<br />To convert this exponential equation into a logarithmic equation, we need to understand the definition of a logarithm. A logarithm is the power to which a number must be raised to get another number.<br /><br />## Step 3<br />In the given equation, the base is 2, the exponent is -3, and the result is \(\frac {1}{8}\). Therefore, the logarithmic form of this equation would be: "log base 2 of \(\frac {1}{8}\) equals -3".