Write the log equation as an exponential equation. You do not need to solve for x. log(x^2+4x+17)=2

The given equation is in logarithmic form: $log(x^{2}+4x+17)=2$. To convert this to exponential form, we use the definition of a logarithm: if $log_b(a)=c$, then $b^c=a$. In this case, the base of the logarithm is 10 (since no base is specified, it is assumed to be 10), the argument of the logarithm is $x^{2}+4x+17$, and the value of the logarithm is 2. Therefore, the exponential form of the equation is $10^2=x^{2}+4x+17$.