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- 4.) Two charges, it +0.005C charge and a+0.006c charge, are 2 meters apart. a. Galoulate the electric force between them. b. is this force repulsive or altraotive? __ 6.) A small metal sphere with a charge of -2.10times 10^-6C is to the left of another sphere will charge of +1.50times 10^-6C They experience a force of 70,8 N to the left. a. Calculate the distance between them. b. Is this force repulsive or attractive? __ 6.) A helium atom consists of two protons and two electrons that are 7.2times 10^-11 m apart. See Table on the front for the charges of the electrons and protons. a. Calculate the electric force ) A charge of 1.5^ast 10^-7C is placed .128 m from a second charge.If the forco between the charges is 22.6 N what is the magnitude of the second charge? 5.2.0times 10^-2 6.1.78times 10^-7
- Which of the following Is most likely the velocity of a molecule In a vacuum? 2m/sec 200m/sec 1m/sec 20m/sec
- Three point charges, q_(1),q_(2) and q3, lie along the x-axis at x=0,x=3.0cm and x=5.0 cm, respectively. Calculate the magnitude and the direction of the electric force on each of the three point charges wher q_(1)=+6.0mu C,q_(2)=+1.5mu C and q_(3)=-2.0mu C a. Draw the force diagram for this problem.
- 6. Name: __ Date: __ __ Calculating Impulse and Change in Momentum p=m(v) Delta meanschangein p=momentum Delta p=m(v_(f)-v_(1)) m=mass F(t)=m(v_(f)-v_(i)) v_(f)=velocity final v_(i)=velocity initial or beginning F=forcet=time Ap 1. m What is the change in momentum of a 1000 kg car moving from 1m/s to 8m/s v_(f) Delta p=m(v_(f)-v_(i)) Delta p=1000(8-1) Delta p=1000(7) Delta p=underline ( ) 2. A tennis ball may leave a top player's racket on the serve with a speed of 65.0m/s If m Ap the ball's mass is 0.0600 kg, what is the change of momentum of the ball if it started from rest? How much force is required to stop a 60 kg person traveling at 30m/s during a time of: a. 5.0 seconds __ b. 0.50 seconds __ c. 0.05 seconds __ 4. A 1200-kg car is brought from 25m/s to 10m/s over a ti time period with a force c of -600N Determine the time it took for this change in momentum. A 0.10-kg hockey puck decreases its speed from 40m/s to 0m/s in 0.025 seconds. Determine the force that it experiences. A force of 6.0 N acts on a 4.0 kg object for 10.0s. What is the object's change in momentum?
- What was thep reason for the sa fety test at Reactor -4 of the Chernobyl power plant To upgrade the reactor's safety features To test the cooling system under high power To simulate an emergency evacuation scenario To determine if the plant could produce enough energy without power supply
