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Question 1-3 TRAVEL Stacy flew an airplane for 2 hours at x miles per hour, and then she flew another 3 hours at (x+25) miles per hour. The entire distance she flow was 1000 miles Stacy flew at a rate of square miles per hour for 2 hours and square - miles per hour for 3 hours

Problemas

Question 1-3
TRAVEL Stacy flew an airplane for 2 hours at x miles per hour, and then she flew another 3 hours at
(x+25)
miles per hour. The entire distance she flow was 1000 miles
Stacy flew at a rate of square  miles per hour for 2 hours and square  - miles per hour for 3 hours

Question 1-3 TRAVEL Stacy flew an airplane for 2 hours at x miles per hour, and then she flew another 3 hours at (x+25) miles per hour. The entire distance she flow was 1000 miles Stacy flew at a rate of square miles per hour for 2 hours and square - miles per hour for 3 hours

Solución

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Rodrigomaestro · Tutor durante 5 años
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To solve this problem, we need to find the values of x and (x+25) that satisfy the given conditions.<br /><br />Given information:<br />- Stacy flew an airplane for 2 hours at x miles per hour.<br />- She then flew another 3 hours at (x+25) miles per hour.<br />- The entire distance she flew was 1000 miles.<br /><br />Let's denote the distance Stacy flew at x miles per hour as D1 and the distance she flew at (x+25) miles per hour as D2.<br /><br />We can use the formula: Distance = Speed × Time to find the values of D1 and D2.<br /><br />D1 = x × 2<br />D2 = (x+25) × 3<br /><br />The total distance Stacy flew is the sum of D1 and D2, which is 1000 miles.<br /><br />D1 + D2 = 1000<br />x × 2 + (x+25) × 3 = 1000<br /><br />Simplifying the equation:<br />2x + 3(x+25) = 1000<br />2x + 3x + 75 = 1000<br />5x + 75 = 1000<br />5x = 925<br />x = 185<br /><br />Therefore, Stacy flew at a rate of 185 miles per hour for 2 hours and (185+25) = 210 miles per hour for 3 hours.
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