Find the sum of the first 10 terms of the following sequence.Round to the nearest hundredth if necessary. 73,65.7. 59.13. __ Sum of a finite geometric series: S_(n)=(a_(1)-a_(1)r^n)/(1-r) square

## Step 1<br />The given sequence is a geometric sequence. A geometric sequence is a sequence of numbers where each term after the first is found by multiplying the previous term by a fixed, non-zero number called the common ratio.<br /><br />## Step 2<br />In this case, the common ratio (r) can be found by dividing any term by its preceding term. For example, \( \frac{65.7}{73} \), \( \frac{59.13}{65.7} \), etc.<br /><br />## Step 3<br />The formula for the sum of the first n terms of a geometric sequence is given as:<br />### \( S_{n}=\frac {a_{1}-a_{1}r^{n}}{1-r} \)<br />where \( S_{n} \) is the sum of the first n terms, \( a_{1} \) is the first term, r is the common ratio, and n is the number of terms.<br /><br />## Step 4<br />Substitute the values of \( a_{1} \), r, and n into the formula to find the sum of the first 10 terms.