Jason has some quarters and dimes. He has 22 coins worth a total of 3.55 . How many of each type of coin does he have? Number of quarters: square Number of dimes: square

Let's denote the number of quarters as $q$ and the number of dimes as $d$. We are given two equations based on the problem statement:1. The total number of coins is 22: $q + d = 22$2. The total value of the coins is $3.55, or 355 cents: $25q + 10d = 355$We can solve this system of equations using substitution or elimination. Here, I'll use the substitution method.Step 1: Solve the first equation for one of the variables. Let's solve for $d$: $d = 22 - q$Step 2: Substitute the expression for $d$ into the second equation and solve for $q$: $25q + 10(22 - q) = 355$ $25q + 220 - 10q = 355$ $15q = 355 - 220$ $15q = 135$ $q = \frac{135}{15}$ $q = 9$Step 3: Now that we have the number of quarters, we can find the number of dimes by substituting $q$ back into the equation $d = 22 - q$: $d = 22 - 9$ $d = 13$Answer:Jason has 9 quarters and 13 dimes.Number of quarters: $\boxed{9}$Number of dimes: $\boxed{13}$