Find the product.Simplify your answer. (3c-4)(2c-1) square

To find the product of \((3c-4)(2c-1)\), we will use the distributive property (also known as the FOIL method for binomials). FOIL stands for First, Outer, Inner, Last, which refers to the terms we multiply together.<br /><br />1. **First**: Multiply the first terms in each binomial:<br /> \[<br /> 3c \cdot 2c = 6c^2<br /> \]<br /><br />2. **Outer**: Multiply the outer terms in the binomials:<br /> \[<br /> 3c \cdot -1 = -3c<br /> \]<br /><br />3. **Inner**: Multiply the inner terms in the binomials:<br /> \[<br /> -4 \cdot 2c = -8c<br /> \]<br /><br />4. **Last**: Multiply the last terms in each binomial:<br /> \[<br /> -4 \cdot -1 = 4<br /> \]<br /><br />Now, combine all these products:<br />\[<br />6c^2 - 3c - 8c + 4<br />\]<br /><br />Next, combine the like terms \(-3c\) and \(-8c\):<br />\[<br />6c^2 - 11c + 4<br />\]<br /><br />So, the simplified product of \((3c-4)(2c-1)\) is:<br />\[<br />\boxed{6c^2 - 11c + 4}<br />\]