5x+y=6 5x+3y=-4 The y-coordinate of the solution to the system shown is __ -1 (1)/(2) 1 -5

To solve the system of equations, we can use the method of substitution or elimination. In this case, we can use the elimination method.<br /><br />First, let's multiply the first equation by 3 and the second equation by 1 to make the coefficients of y the same in both equations:<br /><br />$15x + 3y = 18$<br />$5x + 3y = -4$<br /><br />Now, we can subtract the second equation from the first equation to eliminate y:<br /><br />$(15x + 3y) - (5x + 3y) = 18 - (-4)$<br />$10x = 22$<br />$x = \frac{22}{10}$<br />$x = 2.2$<br /><br />Now that we have the value of x, we can substitute it back into either of the original equations to solve for y. Let's use the first equation:<br /><br />$5x + y = 6$<br />$5(2.2) + y = 6$<br />$11 + y = 6$<br />$y = 6 - 11$<br />$y = -5$<br /><br />Therefore, the y-coordinate of the solution to the system is -5.