10. How can the polynomial x^wedge 2+10x+25 be factored? a (x+5)(x+5) b (x+2)(x+3) c (x-5)(x-5) d (x+10)(x+2)

<br />To factor the polynomial $x^2+10x+25$, we need to find two numbers that multiply to 25 (the constant term) and add up to 10 (the coefficient of the linear term).<br /><br />The numbers that satisfy these conditions are 5 and 5, since $5 \times 5 = 25$ and $5 + 5 = 10$.<br /><br />Therefore, the polynomial can be factored as $(x+5)(x+5)$.<br /><br />So, the correct answer is:<br />a) $(x+5)(x+5)$