Factor 49b^4-64 completely. 49b^4-64= square

<br /><br />First, we recognize that the given expression is a difference of squares. A difference of squares is a perfect square subtracted from another perfect square. It can be factored using the formula: $a^2 - b^2 = (a - b)(a + b)$.<br /><br />In this case, we can rewrite $49b^{4}-64$ as $(7b^2)^2 - 8^2$, which is a difference of squares. <br /><br />So, we can factor it as: $(7b^2 - 8)(7b^2 + 8)$.<br /><br />Therefore, the completely factored form of $49b^{4}-64$ is $(7b^2 - 8)(7b^2 + 8)$.