Select the formula for the n^th term of the sequence. 8,-16,32,ldots Show your work here 8-2(n-1) 8-2(n) 8(-2)^n-1 8(-2)^n None of the above

To find the formula for the $n^{th}$ term of the sequence $8,-16,32,\ldots$, we need to identify the pattern in the sequence.<br /><br />Let's denote the $n^{th}$ term of the sequence as $a_n$.<br /><br />We can observe that each term in the sequence is obtained by multiplying the previous term by $-2$.<br /><br />So, we can write the formula for the $n^{th}$ term as:<br /><br />$a_n = 8(-2)^{n-1}$<br /><br />Therefore, the correct answer is $8(-2)^{n-1}$.